David purchased some cookies at the cost of
5 for $4 (5/4=1.25) and
sold them at 4 for $5(4/5=0.80).
To find cost per cookie subtract 1.25-0.80=0.45
David made a profit of $180 in total ( divide profit per cookie cost: 180/0.45= 400)
How many cookies did David purchase to make that much money?
He needed to make 400 cookie to make the profit of $180.
<h2>
Answer:</h2>
<u>By supplementary angle property</u>,
x + 78° = 180°
x = 180° - 78°
x = 102°.
Answer:
The 99% confidence interval for the proportion of athletes who graduate is (0.5309, 0.7323).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
99% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the proportion of athletes who graduate is (0.5309, 0.7323).
Answer: you need to dived and then you will get your answer
Step-by-step explanation:
First we need to find the cost per chocolate bar aka the unit rate per chocolate bar
We start by taking 3$ and dividing it by 2 which gives us a total of 1.50$ each per chocolate bar
Now that we know that our unit rate is 1.50$ per bar we then do 1.50$ times 6,700 which gives us a total of 10,050$
This means that our answer is 10,050$ meaning you paid 10,050$ for 6,700 chocolate bars
