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Dafna11 [192]
3 years ago
9

Keisha is solving the equation 7^x=9.

Mathematics
1 answer:
olganol [36]3 years ago
3 0
\bf \textit{Logarithm of exponentials}\\\\
log_a\left( x^  b \right)\implies   b\cdot  log_a(x)\\\\
-------------------------------\\\\
7^x=9\implies \boxed{log(7^x)=log(9)}\implies x\cdot log(7)=log(9)
\\\\\\
x=\cfrac{log(9)}{log(7)}
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1) What is the scale factor of dilation when the blue shape is a dilation of the black shape?
Anon25 [30]
B and A is the correct answers
4 0
4 years ago
Given: JP = KP; PX = PY Prove: ΔPYJ ≅ ΔPXK Triangles P Y J and P X K overlap and intersect at point Z. Point X of triangle P X K
FrozenT [24]

Answer:

Prove: ΔPYJ ≅ ΔPXK

Step-by-step explanation:

Overlapping triangles are said to be triangles that share at least part of a side or an angle.

To prove ΔPYJ is congruent to ΔPXK

First we would draw the diagram obtained from the given information.

Find attached the diagram.

Given:

JP = KP

PX = PY

From the diagram, ΔPYJ and ΔPXK share the line KJ (part of the side of each of the triangle)

KJ ≅ KJ (A reflexive property - the segment is congruent to itself)

In ∆PYJ

JP = KP + KJ

In ∆PXK

KP = JP + KJ

Since JP = KP

KP + KJ = JP + KJ

PJ ≅ PK

The overlapping section makes a smaller triangle KXJ

∠K = ∠J (opposite angles of congruent sides are equal)

In ∆PYJ: PY + YJ + PJ (sum of angles in a triangle)

In ∆PXK: PX + XK + PK (sum of angles in a triangle)

If ΔPYJ ≅ ΔPXK

PY + YJ + PJ = PX + XK + PK

XK ≅ YJ

Therefore, ΔPYJ ≅ ΔPXK

4 0
3 years ago
Read 2 more answers
6. the price of an item with a 15% discount
denpristay [2]

The price of an item with a 15% discount would be 85% of the original price, so if the original price was x, the discounted price would be: \frac{85x}{100}

5 0
3 years ago
ANSWER PLZ QUICK AND FAST
Maru [420]

Hello!

If we have 7 more, we are adding. As you can see, we add 7 more to n in C.

Therefore, our answer is C) n+7.

I hope this helps!

4 0
4 years ago
Read 2 more answers
The sum of a student's three score is 246. if the first is 14 points more than the second, and the sum of the first two is 6 mor
mr_godi [17]
Let the second score = x
⇒ second score = x

<span>the first is 14 points more than the second
</span>⇒ first score = x + 14

<span>the sum of the first two is 6 more than twice the third
</span>⇒ third score = 1/2 (x + x + 14 - 6) = x + 4

<span>The sum of a student's three score is 246
</span>⇒ x + (x + 14) + (x + 4) = 246
<span>
Solve x:
</span>x + x + 14 + x + 4 = 246
3x + 18 = 246
3x = 228
x = 76

second score = x = 76
first score = x + 14 = 76 + 14 = 90

Answer: 90
7 0
3 years ago
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