3 years ago

Keisha is solving the equation 7^x=9.

1 answer:

3 0

$\bf \textit{Logarithm of exponentials}\\\\
log_a\left( x^ b \right)\implies b\cdot log_a(x)\\\\
-------------------------------\\\\
7^x=9\implies \boxed{log(7^x)=log(9)}\implies x\cdot log(7)=log(9)
\\\\\\
x=\cfrac{log(9)}{log(7)}$

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