Question

Keisha is solving the equation 7^x=9.

Answer 1

$\bf \textit{Logarithm of exponentials}\\\\ log_a\left( x^ b \right)\implies b\cdot log_a(x)\\\\ -------------------------------\\\\ 7^x=9\implies \boxed{log(7^x)=log(9)}\implies x\cdot log(7)=log(9) \\\\\\ x=\cfrac{log(9)}{log(7)}$