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2 years ago

7

The ordinate of every point on the 0-axis is zero True or False

2 answers:

Sindrei [870]2 years ago

6 0

Answer:

True

Step-by-step explanation:

vodomira [7]2 years ago

5 0

True, if we take any point on y-axis, then the distance of this point from y-axis is zero i.e., x-co-ordinate of every point on y-axis is zero. Therefore, the co-ordinates of a point on y-axis are of the form (0, y).

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The solution to f - (-4) = 12 is f = 8.<br><br><br> True False

amid [387]

Answer:

true

Step-by-step explanation:

as negative takeaway a negative is positive so 8-(-4)= 8+4=12

3 0

2 years ago

Read 2 more answers

During the past year, Zara and Ivan each read 2 books, but George read 7, Ali read 12, and Marsha read 25. The median number of

gogolik [260]

Answer:

D = 7

Step-by-step explanation:

To find the median, we must first list the amount of books each person read, and then put them in order.

2, 2, 7, 12, 25

These are already in order from smallest to greatest, which is awesome. We can then cross out one number from each side until we end up with either one or two numbers. We then find the average of those 1 or 2 numbers to find our median.

2, 3, 7, 12, 25

cross 2 and 25 out

3, 7, 12

cross 3 and 12 out

7

Our median is thus 7

7 0

2 years ago

1 substitute p=5, q=7, r = -2

lora16 [44]

1.

a.) 2q + 5r

2(7) + 5(-2)

14 - 10 = 4

b.) 3(p + 6) + q + r Plug in the numbers

3(5 + 6) + 7 - 2 Solve inside the parentheses first

3(11) + 7 - 2

33 + 5 = 38

2.

a.) m(3m + 4n)

2(3(2) + 4(3))

2(6 + 12)

2(18) = 36

b.) n²(m + p²)

(3)²(2 + (-5)²)

9(2 + 25)

9(27) = 243

c.) 3m(8 + n) + n²

3(2) (8 + 3) + 3²

6(11) + 9

66 + 9 = 75

3 0

2 years ago

1.) What is the equation of the path of firework #1? Write your equation in general form.

valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in $y=ax^2+bx+c$

it's easier to find vertex form first then expand to get general form

vertex form is $y=a(x-h)^2+k$ where the vertex is (h,k) and a is a constant

firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

$h_1=a(t-10)^2+50$

to find the value of $a$ , subsitute another point

(0,0)

$0=a(0-10)^2+50)$

$0=100a+50$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_1=\frac{-1}{2}(t-10)^2+50$

expand to get general form

$h_1=\frac{-1}{2}(t^2-20t+100)+50$

$h_1=\frac{-1}{2}t^2+10t-50+50$

$h_1=\frac{-1}{2}t^2+10t$

2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is $h_2=a(t-10)^2+72$

find $a$

use another point

(0,22)

$22=a(0-10)^2+72$

$22=100a+72$

$-50=100a$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_2=\frac{-1}{2}(t-10)^2+72$

3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50

domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0

2 years ago

Tomtit [17]

This would be 525 / 0.70 = $750 Answer

8 0

2 years ago