2 years ago

(1+sinx/cos^2x) = tan^2x + 1 + tanxsecx

1 answer:

6 0

#ANSWER#

(1+sinx/cos²x) =tan²x+1+tanx . secx

-> [(1+sinx/cos²x)] = 1/cos²x+sinx/
-> cos²x

-> = sec²x+tan x sec x
-> =tan²x+1+tanx secx

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