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MariettaO [177]

3 years ago

14

3/5y + 2/9 = 5/8 - 2/5y + 5/8

2 answers:

Vitek1552 [10]3 years ago

8 0

Answer:

y = 37/36

Step-by-step explanation:

Whitepunk [10]3 years ago

7 0

let's take a peek at the denominators hmmmm 5, 9, 8 hmmmm we can get an LCD of simply their product, well, that'd be 360, so then, let's multiply both sides by the LCD of 360 to do away with the denominators and proceed.

$\bf \cfrac{3}{5}y+\cfrac{2}{9}=\cfrac{5}{8}-\cfrac{2}{5}y+\cfrac{5}{8}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{360}}{360\left( \cfrac{3}{5}y+\cfrac{2}{9} \right)=360\left( \cfrac{5}{8}-\cfrac{2}{5}y+\cfrac{5}{8} \right)} \\\\\\ 72(3y)+40(2)=45(5)-72(2y)+45(5) \\\\\\ 216y+80=225-144y+225\implies 216y+80=450-144y \\\\\\ 216y=370-144y\implies 360y=370\implies y=\cfrac{370}{360}\implies y=\cfrac{37}{36}$

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The diagram shows a right-angled triangle.

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Answer:

Step-by-step explanation:

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2 years ago

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3 years ago

A box in the shape of a rectangular prism has a width that is 5 inches greater than the height and a length that is 2 inches gre

aliina [53]

The volume of the rectangular prism can be express in standard polynomial as follows:

x³ + 12x² + 35x

<h3>How to find the volume of a rectangular prism?</h3>

volume of a rectangular prism = lwh

where

l = length
w = width
h = height

Therefore,

let

height = x

width = x + 5

length = x + 5 + 2 = x + 7

Therefore,

volume = x(x + 5)(x + 7)

volume = x(x² + 7x + 5x + 35)

volume = x(x² + 12x + 35)

volume = x³ + 12x² + 35x

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7 0

2 years ago

If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0

2 years ago