Helpppp!!!!!!?! Need helpb

FUNCION AFÍN O LINEAL. Una empresa de gas cobra el servicio del siguiente modo: un cargo fijo de $140, mas un importe por el con

antoniya [11.8K]

Answer:

El costo es:

Primero tenemos un cargo fijo de $140.

Luego tenemos un $25 por cada m^3 consumido.

Entonces, si tenemos x m^3 consumidos en un mes, el cargo de ese mes va a ser:

C(x) = $140 + $25*x.

Esto es una relación linear.

A) En este caso tendríamos x = 140

C(140) = $140 + $25*140 = $3640

B) La formula es, como ya escribimos arriba, C(x) = $140 + $25*x.

C) El grafico estará al final. En el podemos ver que la linea corta el eje vertical en y = $140, que seria lo minimo que se puede pagar al mes, en el caso de que el consumo sea x = 0.

D) La ordenada al origen es $140, representa el cargo fijo que no depende de la variable x.

5 0

4 years ago

Nicholas sent a chain letter to his friends, asking them to forward the letter to more friends. Every 12 weeks, the number of pe

Digiron [165]

Answer:

$P(t)=50(1.99)^{t/12}$

Step-by-step explanation:

The problem can be modeled by using the compound growth formula.

Given, Initial number P_0 of people who Nicholas sent the chain letter t=50

The growth rate, r =99%=0.99

Period of Growth,k =12 Weeks

$P(t)=P_0(1+r)^{t/k}$

Therefore, in any week (t) after Nicholas initially sent the mail, the number of people who receive the email is modeled by the function:

$P(t)=50(1+0.99)^{t/12}\\\\P(t)=50(1.99)^{t/12}$

4 0

3 years ago

52% of all Americans are home owners. If 45 Americans are randomly selected, find the probability that a. Exactly 21 of them are

Nataly [62]

Answer:

0.0918 ; 0.6277 ; 0.6064; 0.5055

Step-by-step explanation:

Given that :

Proportion of home owners : p = 0.52

Number of trials = 45

Using binomial distribution formula :

P(x =x) = nCr * p^x * (1 - p)^(n-x)

A.) probability that exactly 21 are homeowners :

P(x = 21) = 45C21 * 0.52^21 * (1 - 0.52)^(45 - 21)

P(x = 21) = 45C21 * 0.52^21 * 0.48^24

P(x = 21) = 3773655750150 * 0.52^21 * 0.48^24

P(x = 21) = 0.0918

b. At most 24 of them are are home

Using the binomial probability to save computation time.

P(x ≤ 24) = p(0) + p(1) +.... + p(24)

P(x ≤ 24) = 0.6277

C.) At least 23 of them are home owners.

P(x ≥ 23) = p(23) + p(24) +... + p(45)

P(x ≥ 23) = 0.6064

d. Between 20 and 24 (including 20 and 24) of them are home owners.

P(20 ≤ x ≤ 24) = p(20) + p(21) + p(22) + p(23) + p(24)

P(20 ≤ x ≤ 24) = 0.0711 + 0.0918 + 0.1084 + 0.1175 + 0.1167

P(20 ≤ x ≤ 24) = 0.5055

8 0

3 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame

lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678$

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{207.9 - 208}{0.1678}$

$Z = -0.6$

$Z = -0.6$ has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0

3 years ago

Which function is undefined when theta=pi/2 radians?

Verizon [17]

We know that tanθ = sinθ/cosθ

For a number to be undefined, the denominator must equal to 0. At π/2, the cosθ value is 0 and sinθ is 1. Hence, tan(π/2) is undefined.

Hope I helped :)

4 0

3 years ago

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