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3 years ago

8

Alex buys 2 1/2 pounds of grapes. He buys 1 1/4 times as many pounds of apples as grapes. How many pounds of apples does he buy?

2 answers:

PSYCHO15rus [73]3 years ago

6 0

Grapes = 2 1/2 pounds = 5/2 pounds
Apples = 1 1/4 times grapes = 5/4 times grapes

Apples = 5/4 * 5/2 = 25/8 pounds = 3 1/8 pounds

rusak2 [61]3 years ago

4 0

So if, <span>2 1/2 = 5/2 and 1 1/4 = 5/4,
then </span>5/2 * 5/4 = 5*5 / 2*4 <span>= 25/8 is simplified to 3 1/8 pounds.</span>

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Plz do both of them for me and even show the work plzzzzzz

Vinvika [58]

Answer:

(a)= option 3

(b)= option 3

Step-by-step explanation:

(A) It is given that a sequence is defined by the recursive function $a_{1}=1$ and $a_{n}=a_{n-1}+n$

Now, substituting the value of n=2 in above equation,

$a_{2}=a_{1}+2$

$a_{2}=1+2$

$a_{2}=3$

Again putting n=3,

$a_{3}=a_{2}+3$

$a_{3}=3+3$

$a_{2}=6$

Putting n=4,

$a_{4}=a_{3}+4$

$a_{4}=6+4$

$a_{4}=10$

Putting n=5,

$a_{5}=a_{4}+5$

$a_{5}=10+5$

$a_{5}=15$

Putting n=6,

$a_{6}=a_{5}+6$

$a_{6}=15+6$

$a_{6}=21$

Putting n=7,

$a_{7}=a_{6}+7$

$a_{7}=21+7$

$a_{7}=28$

Hence, option 3 is correct.

(B) The given sequence is :

5, -10, 20, -40, 80.....

Since, the given sequence is GP, therefore

$a_{1}=5$ and r=-2

The nth term is given by:

$a_{n}=a_{1}r^{n-1}$

For fifteenth term, put n=15 in above equation, we get

$a_{15}=5(-2)^{14}$

= $5{\times}16384$

= $81920$

Hence, the fifteenth term is 81920.

Option 3 is correct.

5 0

3 years ago

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Nataly_w [17]

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4 years ago

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AVprozaik [17]

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4 years ago

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ikadub [295]

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3 years ago

Evaluate the given integral by changing to polar coordinates. sin(x2 y2) dA R , where R is the region in the first quadrant betw

alexira [117]

Answer:

I = 1.47001

Step-by-step explanation:

we have the function

$f(x,y)=sin(x^2y^2)\\$

In polar coordinates we have

$x=rcos\theta\\y=rsin\theta$

and dA is given by

$dA=rdrd\theta$

Hence, the integral that we have to solve is

$I=\int \limt_2^4 \int \limit_0^{\pi /2}sin(r^4cos^2\theta sin^2\theta)rdrd\theta$

This integral can be solved in a convenient program of your choice (it is very difficult to solve in an analytical way, I use Wolfram Alpha on line)

I = 1.47001

Hope this helps!!!

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3 years ago