The volume of a rectangular prism is its length times width times height, or algebraically,
![V=lwh](https://tex.z-dn.net/?f=V%3Dlwh)
. You may be used to computing volume with numbers, but remember, a variable is a stand-in for a number. So you can solve this in the same way. Substitute
![l=x, w= \frac{x}{2},h= \frac{x}{3}](https://tex.z-dn.net/?f=l%3Dx%2C%20w%3D%20%5Cfrac%7Bx%7D%7B2%7D%2Ch%3D%20%5Cfrac%7Bx%7D%7B3%7D%20)
into the formula for volume. You get
![(x)( \frac{x}{2})( \frac{x}{3} )](https://tex.z-dn.net/?f=%28x%29%28%20%5Cfrac%7Bx%7D%7B2%7D%29%28%20%5Cfrac%7Bx%7D%7B3%7D%20%29)
, and you multiply these factors together. As you would with ordinary fractions, multiply the numerators and denominators across. You get
![\frac{(x)(x)(x)}{(1)(2)(3)} = \frac{x^3}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x%29%28x%29%28x%29%7D%7B%281%29%282%29%283%29%7D%20%3D%20%20%5Cfrac%7Bx%5E3%7D%7B6%7D%20)
. It seems that the book wants you to simplify by bringing the 6 up to the denominator. Recall the rule
![x^{-n}= \frac{1}{x^n}](https://tex.z-dn.net/?f=x%5E%7B-n%7D%3D%20%5Cfrac%7B1%7D%7Bx%5En%7D%20)
, if n is non-negative. The opposite applies so that
![\frac{1}{6} = 6^{-1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B6%7D%20%3D%206%5E%7B-1%7D)
. For your final answer, you write
![6^{-1}x^3](https://tex.z-dn.net/?f=6%5E%7B-1%7Dx%5E3)
. This corresponds to
answer choice B.
Answer:
P = 128 Post
Step-by-step explanation:
Total post needed = 216 posts
Number of post Jerry has = 88 posts
Number of posts jerry still needs = P
Total = Number of post Jerry has + Number of posts jerry still needs
216 = 88 + P
216 - 88 = P
128 = P
P = 128 Post
Answer:
By calculating the profit that will keep the business going
I think you divide 18.96 by 3 to get the amount for one pound cost then go pound for pound there