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Ivahew [28]
3 years ago
13

John's age is 4 more than 3 time Mike's age. If their sum is 20, how old are Mike and John?

Mathematics
1 answer:
natima [27]3 years ago
6 0
Let me help you with this :)

John = x 
Mike = y

x = 4 + 3y (4 more than 3 times)

x + y = 20 (we put the x above into this equation)

4 + 3y + y = 20 
4y = 16 (we transfers the 4 on the left side to the right side and subtract it from the 20)
y = 4 (the answer is 4)

we use this for the equation:

x = 4 +3*4
x = 16

John is 16 years old and Mike is 4 years old :)

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So amount of decay in one hour = a - 0.9904a

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Percentage decay every hour = \frac{\text{Amount of decay}}{\text{Initial amount}}\times 100

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