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alekssr [168]
2 years ago
12

1 – 7k + 3k 2 + 10k + 7 – 5k 2

Mathematics
2 answers:
Katyanochek1 [597]2 years ago
8 0

1) The variables are "k"

2) There are 4 terms

3) The coefficients are k

4) The constants are -7, 3, 10, -5

5) The like terms is -7k, 3k, 10k, -5k

The answers are pretty direct but, hope this answers your question.

Have a great day/night!

Nimfa-mama [501]2 years ago
8 0
The variables are k ( the letters)

there are 6 terms (they are separated by plus, minus, etc... signs)

the coefficients are 7, 3, 10, and 5!

the constants are 1, 2, 7, and 2

the like terms is 1k + 16

have a great day/night whatever it is!
(sorry you had to wait lol)
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Answer: 277 ways

Step-by-step explanation:

Let’s start bycreating 10-unit pieces using the 4-unit piece.

The arrangements are:

1). 4-3-3 (3 permutations)

2). 4-3-2-1 = 4! = 24 permutations.

3). 4-3-1-1-1 (5*[4!/(3!1!)]

= 5*4

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4). 4-2-2-2 (4 permutations)

5). 4-2-2-1-1 (5 *[4!/(2!2!)]

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= 30 permutations

6). 4-2-1-1-1-1(6*[5!/(4!1!)]

= 6*5

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Let’s-consider the arrangements using one or more3-unit pieces and no 4-unit piece:

7). 3-3-2-2 (4!/(2!2!)

8). 3-3-2-1-1 (5*(4!/(2!2!)

= 5*6

= 30 permutations.

9). 3-3-1-1-1-1 (6!/(4!2!) = 0

10). 3-2-2-2-1 (5*4!/(3!1!)

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= 20permutations

11). 3-2-2-1-1-1 (6*5!/(3!2!)

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= 60 permutations

Finally we would look at the arrangements using only 1-and 2-unit pieces:

12). 2-2-2-1-1-1-1 (7!/(4!3!)

= 35 permutations

add them all up:

(3 + 24 + 20 + 4) + (30 + 30 + 6 + 30) + (15 + 20 + 60 + 35)

=51 + 96 + 130

= 277ways

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Answer:

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