Question

If 7(3x+9) and 21x + T are equivalent, what is the value of T?

Answer 1

Answer:

$T=63$

Step-by-step explanation:

Given:

$7(3x+9)$  and $21x+T$ are equivalent.

Find value of T?

The $7(3x+9) and 21x+T$ are equivalent. therefore the equation is

$7(3x+9) = 21x+T$

$21x+63=21x+T$

$T = 21x+63-21x$

Here positive $21x$ and negative $21x$ is cancelled.

$T = 63$

So, the value of $T=63$