Sep 08, 12:33:18 AM
1 answer:
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Refer to the diagram shown below.
w = 6 7/8 in = 6.875 in, the width of each device.
d = 3 1/2 in = 3.50 in, the space between teo devices.
The total space needed is
D = 4(w+d) + w
= 5w + 4d
= 5*6875 + 4*3.5
D = 48.375 in or 48 3/8 in
Answer: 48 3/8 inches or 48.375 inches
w = 6 7/8 in = 6.875 in, the width of each device.
d = 3 1/2 in = 3.50 in, the space between teo devices.
The total space needed is
D = 4(w+d) + w
= 5w + 4d
= 5*6875 + 4*3.5
D = 48.375 in or 48 3/8 in
Answer: 48 3/8 inches or 48.375 inches
A=futurer amount
P=present amount
r=rate in decimal
n=number of times compounded per year
t=time in years
A=2500
r=0.05
n=2
t=2
divide both sides by [tex} 1.025^{4} [/tex]
2264.88=P
he should invest
$2264.88