Question

Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Find the 87 th percentile.

Answer 1

Answer:

  57.885

Step-by-step explanation:

For such calculations a probability calculator is very helpful. The one in the attachment shows the 87th percentile to be 57.885.

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A table of the standard normal distribution will tell you the 87th percentile corresponds to a z-value of 1.12639. Then the X value is ...

  X = Zσ +μ = 1.12639(7) +50 = 57.885