Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Find the 87 th pe
rcentile.
1 answer:
Answer:
57.885
Step-by-step explanation:
For such calculations a probability calculator is very helpful. The one in the attachment shows the 87th percentile to be 57.885.
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A table of the standard normal distribution will tell you the 87th percentile corresponds to a z-value of 1.12639. Then the X value is ...
X = Zσ +μ = 1.12639(7) +50 = 57.885
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Answer:
Step-by-step explanation:
So we have the equation:
And we want to solve for R.
First, let's multiply both sides by J to remove the fraction on the right. So:
Simplify the right:
We can rewrite our equation as:
So, to isolate the R variable, divide both sides by I²t:
The right side cancels, so:
And we are done!