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3 years ago

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At a local animal shelter last week, 1/4 of the pet adoptions placed cats into homes and 2/3 of the adoptions placed dogs. Hamst

ers, rabbits, and reptiles were also adopted. Which choice is the MOST reasonable for the part of the adoptions for cats and dogs? A) 1/12 B) 5/12 C) 1/2 D) 11/12

2 answers:

Arada [10]3 years ago

7 0

Answer:

B)5/12 Hope It Help

Step-by-step explanation:

Brainliest please

Temka [501]3 years ago

3 0

Answer:d I think?

Step-by-step explanation:

You might be interested in

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

BRAINLY AND POINTS FOR STEP BY STEP<br> b-4z =a for b<br> ____<br> 5

fgiga [73]

Answer:

Dividing both sides of 5x = 4 by 5 yields x = 4 _. 5 . The value of x can now be ... tuting −1 for a into the equation b = –a + 3 gives b = −(−1) + 3, or b = 4. ... ___. 82 − (2i)2 . Since i2 = −1, this can be simplified to 24 − 6i − 40i − 10. __.

hope this helps also Brainliest please:)

7 0

3 years ago

Read 2 more answers

Solve for x Solve for x Solve for x

ANEK [815]

9514 1404 393

Answer:

x = 3

Step-by-step explanation:

The two right triangles share angle A, so the similarity statement can be written ...

ΔABC ~ ΔADE

Corresponding sides are proportional, so we have ...

BC/DE = AB/AD

x/12 = 3/(3+9)

x = 3 . . . . . . . . . . multiply by 12

6 0

3 years ago

2. The general equation of a plane is Ax + By + Cz = D, where A, B, C, and D are real numbers and A is nonnegative. Find the equ

lidiya [134]

Z=6-(3/4)y-2x
<span>z+(3/4)y+2x=6 </span>

<span>By connecting the three points in the graph, Got this equation by isolating each plane to figure it out. </span>

3 0

3 years ago

Read 2 more answers

looks out from the crown of the Statue of Liberty, approximately 250 ft above ground. The tourist sees a ship coming into the ha

Zigmanuir [339]

Answer:

The distance from the base of the statue to the ship is 771.60 ft

Step-by-step explanation:

Refer the attached figure

Height of statue AB= 250 feet

The tourist sees a ship coming into the harbor and measures the angle of depression as 18°.

So, ∠ACB = 18°

We are supposed to find the distance from the base of the statue to the ship i.e. BC

In ΔABC

$Tan \theta = \frac{Perpendicular}{Base}$

$Tan 18^{\circ}=\frac{AB}{BC}$

$Tan 18^{\circ}=\frac{250}{BC}$

$BC=\frac{250}{Tan 18^{\circ}}$

$BC=\frac{250}{0.324}$

BC=771.60 ft

Hence the distance from the base of the statue to the ship is 771.60 ft

3 0

3 years ago