Use the Pythagorean theorem since you are working with a right triangle:
a^2+b^2=c^2a2+b2=c2
The legs are a and b and the hypotenuse is c. The hypotenuse is always opposite the 90° angle. Insert the appropriate values:
0.8^2+0.6^2=c^20.82+0.62=c2
Solve for c. Simplify the exponents (x^2=x*xx2=x∗x ):
0.64+0.36=c^20.64+0.36=c2
Add:
1=c^21=c2
Isolate c. Find the square root of both sides:
\begin{gathered}\sqrt{1}=\sqrt{c^2}\\\\\sqrt{1}=c\end{gathered}1=c21=c
Simplify \sqrt{1}1 . Any root of 1 is 1:
c=c= ±11 *
c=1,-1c=1,−1
Answer:
x-independent
y-dependent
Step-by-step explanation:
Dependent variable: y because you get the points by doing the quiz.
Independent variable: x because you don’t know how many questions you answered correctly.
Total points you score: Unknown until you know how many you got right also the same as y.
Number of questions you answer correctly: Unknown until you get your paper back, also the same as x.
Read more on Brainly.com - brainly.com/question/9741421#readmore
Answer:
210°
Step-by-step explanation:
Given
sinΘ = - 
Note taken the inverse sine of the positive value of the ratio, gives the related acute angle, that is
Θ = 
( ) = 30° ← related acute angle
Thus the required angle in the third quadrant is
Θ = 180° + 30° = 210°
The general equation of second degree is
Ax²+By²+Gx+Fy+C=0 ------1
Now the given conditions are
A=1, B=0, C=0
Now,
putting in eq. 1
x²+Gx+Fy=0
x²+Gx= -Fy
For completing square, add both side (G/2)²
x²+Gx+(G/2)²=-Fy+(G/2)²
(x+G/2)²=-F(y-G²/4F)
Or
X²=-FY where X=x+G/2, Y=y-G²/4F
which is the standard eq. of parabola in XY-coordinate.
