Distribution is multiplying. So
6(12)-6(5)
72-30
42
The normal distribution curve for the problem is shown below
We need to standardise the value X=405.5 by using the formula


We now need to find the probability of z=0.32 by reading the z-table
Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

from the z-table, the reading

gives 0.6255
hence,

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%
Answer:
41/6
Step-by-step explanation:
-12+81=-1+6(2a-2)
first distribute:
-12+81=-1+12a-12
combine like terms:
<u>-12+81</u>= <u>-1</u>+12a<u>-12</u>
69=-13+12a
add -13 with 69:
82=12a
divide 82 and 12:
82/12= 41/6
Answer:
6
Step-by-step explanation:
Since RQ bisects WRV, WRQ = QRV, 48=7y+6. 48-6=42, leaving 42=7y. 42/7=6.
Answer:
Q.#1 is a
Q.#2 is d
Step-by-step explanation:
hope this helps:)