Question

Two fair dice are tossed, and the up face on each die is recorded. Find the probability of observing each of the following events. Answer in fraction form or decimal approximation with 4 decimal places: A:{A:{ A 5 does not appear on either die }} B:{B:{ The difference of the numbers is 2 }} C:{C:{ The sum of the numbers is 10 or more }

Answer 1

• Answer:

1. Probability of getting a die which 5 does not appear on each side is 5/6
2. probability of getting numbers of which the difference is 2 is 1/9
3. Probability of obtaining numbers that the sum is equal to or greater than 10 is 1/12

Step-by-step explanation:

When two dies are tossed, possible outcomes are (1,1) (1,2) ,(1,3) (1,4), (1,5) (1,6),(2,1) (2,2) (2,3) (2,4) (2,5) (2,6), (3,1)(3,2)(3,3)(3,4),(3,5)(3,6)(4,1) (4,2),(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

so the total sample space =36

From de possible outcome, probability of getting a die that five does not appear on either side is given by total outcome of not getting five from either side/sample space

=30/36 = 5/6

And also probability of getting the difference of numbers to be 2 are (3,1)(4,2) (5,3) (6,4) =4outcomes

the probability of getting a difference of 2 is given by outcome/sample space 4/36 = 1/9

probability of getting the summation of two numbers to be equal to or greater than ten are; Outcome/sample space.

the outcome are (4,6) (5,5) (5,6)(6,4)(6,5)and (6,6)= 6outcomes

=6/36 =1/12.