I think I may be missing something ... I don't completely understand your question.
All you need to make a fraction is two numbers and a bar. The bar can be either
horizontal or slanty. Then you write one number on top and the other number on
the bottom, and bada-bing, you have a fraction.
You can make fractions like
2700 / 600
27 / 6
9 / 2 (all 3 of these have the same value)
600 / 2700
6 / 27
2 / 9 (all 3 of these have the same value)
Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
see explanation
Step-by-step explanation:
(a)
OC = OB ( both radii of the circle )
Thus Δ BOC is isosceles with congruent base angles.
∠ BOC = ∠ BCO = 50°
(b)
∠ ACB = 90° ( angle in a semicircle ), then
∠ ACO = 90° - 50° = 40°
OA = OC ( both radii of the circle )
Thus Δ ACO is isosceles with congruent base angles.
∠ BAC = ∠ ACO = 40°
Answer:
Step-by-step explanation:
The equation for a circle is given by:
Where (h,k) is the center and r is the radius.
The center is the red dot, which is (1,2). Thus, h=1 and k=2.
To find the radius, you need to use the distance formula. We are given two coordinates: the center (red dot) at (1,2) and a blue dot on the circle at (2.5,4). Find the radius by using the distance formula:
Let (1,2) be <em>x₁ </em>and <em>y₁ </em>and let (2.5,4) be <em>x₂ </em>and <em>y₂. </em>Therefore:
Thus, r is 2.5.
Plugging these numbers into the equation, we have:
