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horsena [70]
3 years ago
10

Rite 18.725 as a mixed number in simplest form.

Mathematics
1 answer:
Mila [183]3 years ago
5 0

18.725 = 18725/1000 = 3745/200 = 749/40 = 18 29/40

so, your answer is 18 29/40

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A cylindrical vase has a diameter of 6 inches. At the bottom of the vase, there are 8 marbles, each of diameter 3 inches. The va
DIA [1.3K]

Answer:

  π(3 in)²(10 in) -8(4/3)(1.5 in)³

Step-by-step explanation:

The volume of a cylinder with a radius of 3 inches and a height of 10 inches is ...

  V = πr²h = π(3 in)²(10 in)

The volume of 8 spheres with a radius of 1.5 inches is ...

  V = 8(4/3)πr³ = 8(4/3)π(1.5 in)³

The volume occupied by the water is the volume of the cylinder not occupied by the spheres. So, it is ...

  V = π(3 in)²(10 in) -8(4/3)(1.5 in)³ . . . . . . matches the 4th choice

5 0
3 years ago
Pls help .....................
Bad White [126]

Answer:

3rd answer

Step-by-step explanation:

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8 0
2 years ago
(URGENT) need this answer today​
Vlad [161]

Answer: 19.5

Step-by-step explanation:

Use Pythagorean theorem to find the diagonal as it is a right triangle.

6 0
2 years ago
For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
Explain why it works to break apart a number by place values to multiply
Illusion [34]
It works because even if the numbers are broken apart, you are still multiplying the numbers by their values, it's only different because once broken apart, it's in expanded form instead of standard form. It also makes multiplication easier since you don't have to deal with such large numbers.
6 0
3 years ago
Read 2 more answers
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