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4 years ago

you already pulled 520 pressure switches for order you need a total of 780 how many more pressure switches do you need to pull

Mathematics

1 answer:

djverab [1.8K]4 years ago

8 0

subtract

780-520 = 260

you need to pull 260 more

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200+5-4+e+9000+100-200

svet-max [94.6K]

Answer:

9103.71828183

Step-by-step explanation:

9103.71828183=200+5-4+e+9000+100-200

7 0

3 years ago

A cyclist traveled 70km at a constant speed. Write down the formula that shows the dependence of the speed, v, on the time t. Fi

aleksandr82 [10.1K]

The equation which relates speed, V and time, t to the total distance traveled is 70 = Vt

70 = Vt
v(5) = 14
V(7) = 10
V(3.5) = 20

Since he is traveling at a constant speed, the relationship between, V and t can be written thus :

Distance = speed × time
70 = Vt

At time, t = 5

70 = 5V
V = 70/5 = 14

At time, t = 7

70 = 7v
V = 70/7 = 10

At time, t = 3.5

70 = 3.5v
v = 70/3.5 = 20

Therefore, the relationship between V and t with distance is 70 = Vt

Learn more :brainly.com/question/23774048

8 0

2 years ago

Rearrange t= 5s + 4 to make s the subject.

STatiana [176]

The answer is 5s= t - 4.

3 0

3 years ago

georgina works on the 30th floor of a office building she took the elevator to the cafeteria on the 7th floor how many floors di

dezoksy [38]

She traveled 23 floors, 30-7=23.

3 0

3 years ago

Read 2 more answers

Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1

GalinKa [24]

Answer:

$-2,\ -1,\ -\dfrac{1}{2},\ 3.$

Step-by-step explanation:

Consider polynomial $2x^4+x^3-14x^2-19x-6.$

If x=-2 is its zero, then you can divide the polynomial $2x^4+x^3-14x^2-19x-6$ by $x+2$ and get

$2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).$

If x=-1, then the polynomial $2x^4+x^3-14x^2-19x-6$ can be rewritten as

$2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).$

The quadratic polynomial has roots

$x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.$

Then the polynomial $2x^4+x^3-14x^2-19x-6$ has zeros $-2,\ -1,\ -\dfrac{1}{2},\ 3.$

7 0

3 years ago