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Sergio [31]
2 years ago
6

Mr. Mole left his burrow and started digging his way down.

Mathematics
1 answer:
asambeis [7]2 years ago
5 0
2.3 meters per minute. -7 is the start of Mr. Mole’s descend and the slope is -2.3. Since it is looking for a measurement, however, it is positive.
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Please Help
leonid [27]
The answer is D because microcosm is a community displaying characteristics of something larger.
4 0
3 years ago
Y/3 - 9 = 12 And tell me how to show work pls.
ella [17]

Answer:

63

Step-by-step explanation:

so y/3 - 9 = 12, add 9 on both sides and you get y/3 = 21. Then you multiply both sides by 3, y/3 * 3, the 3's cancel out, 21 * 3 = 63. You get y = 63

So basically just do + 9 on both sides then *3 on both sides (do it step by step)

3 0
2 years ago
Read 2 more answers
At the farm, corn costs $2.50 per pound. How much would 3 1/2 pounds of corn cost? Write your answer in dollars and cents.
igomit [66]

Multiply price per pound by total pounds:

2.50 x 3.5 = 8.75

Total cost = $8.75

4 0
3 years ago
Read 2 more answers
10,000 kilometers = how many miles
GREYUIT [131]

Answer:

10,000 Kilometers =

6,213.7119 Miles

(

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal with a mean of 16.12 OZ and a
elena-14-01-66 [18.8K]

Answer: 90.82%

Step-by-step explanation:

Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .

Mean : \mu=16.12\text{ OZ}

Standard deviation: \sigma=0.09\text{ OZ}

Let X be the random variable that represents the amount of soda in bottles.

Formula for z-score : z=\dfrac{x-\mu}{\sigma}

Z-score for 16 oz: z=\dfrac{16-16.12}{0.09}=-1.33

Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_

P(x>60)=P(z>-1.33)=1-P(x\leq-1.33)=1-0.0917591=0.9082409\approx0.9082\approx90.82\%

Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .

8 0
3 years ago
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