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Verdich [7]
3 years ago
12

-3 3/8 x -2/3 divided by(-1 3/4)

Mathematics
2 answers:
alex41 [277]3 years ago
7 0

\bf \stackrel{mixed}{-3\frac{3}{8}}\implies -\cfrac{3\cdot 8+3}{8}\implies \stackrel{improper}{-\cfrac{27}{8}}~\hfill \stackrel{mixed}{-1\frac{3}{4}}\implies -\cfrac{1\cdot 4+3}{4}\implies \stackrel{improper}{-\cfrac{7}{4}} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{from left to right}}{-\cfrac{\stackrel{9}{~~\begin{matrix} 27 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{4}{~~\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\times -\cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\div -\cfrac{7}{4}}\implies \cfrac{9}{4}\div -\cfrac{7}{4}

\bf \cfrac{9}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\times-\cfrac{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{7}\implies -\cfrac{9}{7}

Tom [10]3 years ago
6 0
Do PEMDAS first, and then try to come up with the answer according to pemdas. (:
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The Mercury Electric Company issued 2,000,000 shares of stock at $62.50 per share. These selling expenses are deducted: commissi
stealth61 [152]
 Total expense= sum of all expenses incurred 
                       = commission+legal fees+advertising+printing cost+accounting fees

Total amount of shares sold=$ 2000000 x $62.5
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3 0
3 years ago
A, B, and C are collinear, and B is between A and C. The ratio of AB to AC is 1:2 If A is at (6,3) and B is at (-1,2), what are
Maksim231197 [3]

Answer:

The coordinates of C is (-8,1)

Step-by-step explanation:

Looking at the attached image, you'd see that, AB is 1 and BC is 1, that's because we are told that ratio of AB to AC is 1:2 meaning, AC is 2 and AB is 1. Therefore for that ratio to be satisfied BC has to be 1 so that AC would be 2.

Now let's assume the coordinates of C is (x,y).

To get it's coordinates, we use the section formula:

(x,y)= (\frac{mx + nx_{1}}{m + n} , \frac{my + ny_{1}}{m + n})

Where (m,n) is the (AB, BC)

Therefore we have

(-1,2) = (\frac{1\times x + 1\times6}{1 + 1} , \frac{1\times y + 1\times3}{1 + 1})

This gives:

(-1,2) = (\frac{x + 6}{2} , \frac{y + 3}{2})

-1 =( \frac{x + 6}{2} and 2 = \frac{y + 3}{2})

From there x = -8 and y = 1

Therefore the coordinates of C is (-8, 1).

7 0
3 years ago
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kolezko [41]
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