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Nadusha1986 [10]
4 years ago
6

Infants-free

Mathematics
1 answer:
stepan [7]4 years ago
8 0
About $350 because if you add all them up it will give you a fraction and then simplify that fraction and you get your answer

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Divide partial quotient 308 divide by 4
Inessa [10]

Answer:

77 is the answer your welcome

6 0
3 years ago
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Yep here we go again:
vesna_86 [32]

Answer:

100 - 35 = 65 %

Step-by-step explanation:

you need to do math by 100 % and 35% woth a minus and it will become 65

5 0
3 years ago
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What is the awnser to 0.96 in fraction form and have the fraction in simplist form
natali 33 [55]
0.96=\frac{96}{100}=\frac{24}{25}
5 0
4 years ago
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(3xy/3x^2-12)*(x^2+3x+2/xy+y)
TiliK225 [7]

Value of expression (3xy/3x^2-12)*(x^2+3x+2/xy+y) is  \frac{x}{x-2} .

<u>Step-by-step explanation:</u>

Here we need to evaluate expression : (3xy/3x^2-12)*(x^2+3x+2/xy+y)  or ,

(3xy/3x^2-12)*(x^2+3x+2/xy+y)

Let's simplify this

⇒ (\frac{3xy}{3x^2-12})(\frac{x^2+3x+2}{xy+y})

Factorizing the terms we get:

⇒ (\frac{3xy}{3(x^2-4)})(\frac{x^2+2x+x+2}{y(x+1)})              { a^2-b^2=(a+b)(a-b)      }

⇒ (\frac{xy}{(x-2)(x+2)})(\frac{x(x+2)+1(x+2)}{y(x+1)})

⇒ (\frac{xy}{(x-2)(x+2)})(\frac{(x+1)(x+2)}{y(x+1)})

Cancelling similar terms we get:

⇒ \frac{x}{x-2}

Therefore , Value of expression (3xy/3x^2-12)*(x^2+3x+2/xy+y) is  \frac{x}{x-2} .

3 0
3 years ago
Question 7
Papessa [141]

269 armies have higher than 5600 goblin soldiers .

<u>Step-by-step explanation:</u>

Step 1: Sketch the curve.

The probability that X>5600 is equal to the blue area under the curve.

Step 2:

Since μ=5600 and σ=750 we have:

P ( X>5600 ) = P ( X−μ > 5600−5600 )=P ( X−μ/σ>5600−5600/750)

Since Z = x−μ/σ and 5600−5600/750=0 we have:

P ( X>5600 )=P ( Z>0 )

Step 3: Use the standard normal table to conclude that:

P (Z>0)=0.5

We have , 538 armies So , armies have higher than 5600 goblin soldiers is :

⇒ 538(0.5)

⇒ 269

Therefore , 269 armies have higher than 5600 goblin soldiers .

6 0
3 years ago
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