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DerKrebs [107]
3 years ago
14

Here is a picture of a cube, and the net of this cube. What is the surface area of this cube? Enter your answer in the box. cm²

A cube and a net of the cube are shown. The edge length of the cube is labeled 13 centimeters. The net consists of 4 squares connected vertically, and 1 square is attached to the left of the third square and 1 square is attached to the right of the third square. One square in the net is labeled with a side labeled 13 centimeters.
Mathematics
1 answer:
tiny-mole [99]3 years ago
6 0

Answer:

78 cm²

Step-by-step explanation:

since all sides are congruent you multiply the one measurement 6 times,so you do 13 × 6 equals 78

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70 points!!
mafiozo [28]

Answer:

C

C'

1

1. see attached

2. the figure is reflected in the y-axis

Step-by-step explanation:

1.

The given transformation moves each point horizontally to the same

distance on the other side of the y-axis. This is shown in the attachment.

2.

The given rule ...

(x, y) → (-x, y)

is the most precise description of the transformation. In English, it can be

described as a reflection in the y-axis

Step-by-step explanation:

Correct me if I'm wrong

8 0
1 year ago
Can someone help me with this question plzzzzz
Ann [662]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

7d + d - 4d - 7 = 5d

8d - 4d - 7 = 5d

4d - 7 = 5d

5d = 4d - 7

Subtract sides 4d

- 4d + 5d =  - 4d + 4d - 7

d =  - 7

Thus the correct answer is Option three.

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

8 0
2 years ago
9. Arrange 3 519;3951; 3191 in descending order.​
svlad2 [7]

Answer:

3951>3519>3191

Step-by-step explanation:

hope you understood how

3 0
3 years ago
A plan for an executive traveler's club has been developed by an airline on the premise that at least 5% of its current customer
STatiana [176]

Answer:

a) 3.0779

b)2.3264

Step-by-step explanation:

Please see attachment .

7 0
2 years ago
Please help due in 20 minutes
MissTica
  • <PTQ=90

In ∆PTQ

Apply Pythagorean theorem

\\ \tt\hookrightarrow PT^2=PQ^2+QT^2

\\ \tt\hookrightarrow PT^2=15.4^2+9.3^2=323.16

\\ \tt\hookrightarrow PT=17.9

In ∆TRQ

\\ \tt\hookrightarrow tan44.4=\dfrac{QT}{TR}=\dfrac{9.3}{TR}

\\ \tt\hookrightarrow 0.9=\dfrac{9.3}{TR}

\\ \tt\hookrightarrow TR=\dfrac{9.3}{0.9}=10.3

  • PR=PT+TR=10.3+17.9=28.2cm

Now

Area:-

\\ \tt\hookrightarrow 1/2bh

\\ \tt\hookrightarrow 1/2(28.2)(9.3)

\\ \tt\hookrightarrow 14.1(9.3)

\\ \tt\hookrightarrow 131.13cm^2

7 0
1 year ago
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