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Ray Of Light [21]

3 years ago

13

What is the value of s^2t for s = 7 and t = 20? as a whole number

2 answers:

yarga [219]3 years ago

5 0

Answer:

7^40 is umm I don't know sorry

Step-by-step explanation:

But hopefully it's helpful.

Firlakuza [10]3 years ago

4 0

Answer:

steps below

Step-by-step explanation:

if your problem is s²ⁿ = s²*²⁰ = s⁴⁰ (n replace your t)

s²ⁿ = 7⁴⁰ = 6366805760909027985741435139224001

if the problem is s² x 20 = 7² x 20 = 980

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Y= -3+ 2x<br><br> 3x+2y=2<br><br> I need help ASAP <br> What the solution for this someone pls

Delvig [45]

Substitute the 1st equation in the 2nd, we get:

3x + 2(-3 + 2x) = 2
3x -6 +4x = 2

7x = 8
x = 8/7

Replace x = 8/7 in equation 1,

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

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