First thing you gotta do is to sub in the numbers into the equation/expression
<span>uxy = (2)(9)(6)
</span> = 108
* brackets means multiplying
Final answer is 108
What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
1) x=-3. The missing angle is 71 degrees
2) x=45. The missing angles are 90 and 45 degrees.
3) x=40. The missing angles are 40 and 100 degrees
Answer:
b) 6(x + 4)
Step-by-step explanation:
The given word phrase "The product of 4 more than x and 6"
4 more than x = 4 + x
The product "4 + x" and 6
6(x + 4)
Answer: b) 6(x + 4)
