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3 years ago

Anwen walks at an average

Mathematics

2 answers:

Roman55 [17]3 years ago

4 0

Answer:

7 km

Step-by-step explanation:

2 hours 20 minutes is 2 and 1/3 hours. 3 * 2 and 1/3 = 3 * 7/3 = 7km.

amm18123 years ago

3 0

Answer: 7 km

Step-by-step explanation:

In 1 hour, he did 3 km

In 2 hours, he will do 6 km

20 minutes = 20/60 = 1/3

In 20 minutes, he will do 1/3 x 3 = 1 km

So total distance travelled = 7 km

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Bryan had typed his English essay at a constant speed from beginning to end. If he typed

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Answer:

Step-by-step explanation:

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3 years ago

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Lyrx [107]

Answer:

16 sq. yds

Step-by-step explanation:

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2 years ago

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What is the denominator of the simplified expression? (startfraction 2 n over 6 n + 4 endfraction) (startfraction 3 n + 2 over 3

max2010maxim [7]

n/3n - 2.

The denominator of the given simplified expression is

The given expression is ( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 )

To find the denominator of the simplified expression :

First, simplify the given expression as below ;

( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 )

( 2n/2₍₃ₙ ₊ ₂₎ ( 3n + 2/ 3n - 2 ) ( here by taking the common term 2 outside the factor )

= (n/1) ( 1/ 3n - 2 ) ( here by simplifying the factors )

= n/3n - 2.

Therefore, ( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 ) = n/3n - 2

Therefore the result of the given simplified expression is = n/3n - 2.

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2 years ago

Note: Please make sure to properly format your answers. All dollar figures in the answers need to include the dollar sign and an

Daniel [21]

Using the normal distribution, the percentages are given as follows:

a) 9.18%.

b) 97.72%.

c) 50%.

d) 4.27%.

e) 0.13%.

f) 59.29%.

g) 2.46%.

h) 50%.

i) 50%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

For this problem, the mean and the standard deviation are given as follows:

$\mu = 247, \sigma = 60$

For item a, the proportion is the p-value of Z when Z = 167, hence:

$Z = \frac{X - \mu}{\sigma}$

Z = (167 - 247)/60

Z = -1.33.

Z = -1.33 has a p-value of 0.0918.

Hence the percentage is of 9.18%.

For item b, the proportion is the p-value of Z when Z = 367, hence:

$Z = \frac{X - \mu}{\sigma}$

Z = (367 - 247)/60

Z = 2.

Z = 2 has a p-value of 0.9772.

Hence the percentage is of 97.72%.

For item c, the proportion is one subtracted by the p-value of Z when X = 247, hence:

$Z = \frac{X - \mu}{\sigma}$

Z = (247 - 247)/60

Z = 0

Z = 0 has a p-value of 0.5.

Hence the percentage is of 50%.

For item d, the proportion is one subtracted by the p-value of Z when X = 350, hence:

$Z = \frac{X - \mu}{\sigma}$

Z = (350 - 247)/60

Z = 1.72

Z = 1.72 has a p-value of 0.9573.

1 - 0.9573 = 0.0427.

Hence the percentage is of 4.27%.

For item e, the proportion is the p-value of Z when Z = 67, hence:

$Z = \frac{X - \mu}{\sigma}$

Z = (67 - 247)/60

Z = -3.

Z = -3 has a p-value of 0.0013.

Hence the percentage is of 0.13%.

For item f, the proportion is the p-value of Z when X = 300 subtracted by the p-value of Z when X = 200, hence:

X = 300:

$Z = \frac{X - \mu}{\sigma}$

Z = (300 - 247)/60

Z = 0.88.

Z = 0.88 has a p-value of 0.8106.

X = 200:

$Z = \frac{X - \mu}{\sigma}$

Z = (200 - 247)/60

Z = -0.78.

Z = -0.78 has a p-value of 0.2177.

0.8106 - 0.2177 = 0.5929.

Hence the percentage is 59.29%.

For item g, the proportion is the p-value of Z when X = 400 subtracted by the p-value of Z when X = 360, hence:

X = 400:

$Z = \frac{X - \mu}{\sigma}$

Z = (400 - 247)/60

Z = 2.55.

Z = 2.55 has a p-value of 0.9946.

X = 360:

$Z = \frac{X - \mu}{\sigma}$

Z = (360 - 247)/60

Z = 1.88.

Z = 1.88 has a p-value of 0.97.

0.9946 - 0.97 = 0.0246

Hence the percentage is 2.46%.

For items h and i, the distribution is symmetric, hence median = mean and the percentages are of 50%.

More can be learned about the normal distribution at brainly.com/question/24808124

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2 years ago

Which segment in the diagram is skew to BD? A GH B FH C

MariettaO [177]

Theanswer is line segment FH

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3 years ago

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