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yaroslaw [1]
3 years ago
7

If g (x) =x 1/x-2 and h(x) = 4 – x, what is the value of (g*h)(-3)?

Mathematics
1 answer:
Lena [83]3 years ago
4 0
G(x) = (x + 1)/(x - 2) and h(x) = 4 - x
(g * h)(x) = (x + 1)(4 - x)/(x - 2)
(g * h)(-3) = (-3 + 1)(4 - (-3))/(-3 - 2) = (-2)(4 + 3)/(-5) = (-2)(7)/(-5) = -14/-5 = 2.8
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Answer:

\large\boxed{y+5=\dfrac{2}{3}(x-4)}

Step-by-step explanation:

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y-y_1=m(x-x_1)

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We have the equation in the slope-intercept form (y = mx + b)

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Put to the point-slope equation value of the slope and the coordinates of the point (4, -5):

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3 years ago
Are these lines parallel explain?
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Step-by-step explanation: hope it helps

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