Observe the given data distribution table carefully.
The 5th class interval is given as,

The upper limit (UL) and lower limit (LL) of this interval are,

Thus, the upper-class limit of this 5th class is 17.4.
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
Answer:
7-16x=10. I'm sorry I'm not good at math but it never hurts try, right?
Step-by-step explanation:
Multiply the parentheses first which would give you
8-6x+10x-15.
Next add 6x+10x which would give you
8-16x-15.
Then subtract 8-15 which would give you
7-16x=20-5x2. Then work the problem from there.
7-16x=20-10.
7-16x=10.
The variable <em>x </em>is equal to 0.5
Answer:
.6n
Step-by-step explanation:
If we get 40 % off, we still have to pay 100-40 or 60%
The original price is n
We pay 60% of n
60%*n
.60*n
.6n