Answer:
It is not an inverse variation
Length of an arc = theta/360 * 2pi * r
Distance traveled by the tape = 72/360 * 2pi * 18/2 = 18pi / 5
<h3>Solution</h3>
arc DE = 36/360 × (2 × π × 10)
⟹ 1/10 × 20π
⟹ 2π
⟹ 2 × 3.14
⟹ 6.28 ≈ 6.3 cm (third option)
You have the maximum height happens at 5 seconds.
Replace t with 5 and solve for h(t):
h(5) = -0.2(5)^2 + 2(5)
h(5) = -0.2(25) + 10
h(5) = -5+10
h(5) = 5
The maximum height is 5 feet.
Answer:
g(x) = 4, 6, 9, 13.5 for the x-values given
Step-by-step explanation:
The table and graph are attached.