The tower is 61.65 meters tall.
<u>SOLUTION:
</u>
Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,
Then, (let it be) n meter tall 
36.25 long shadow
So, by cross multiplication method,
This can be written as,
Cross multiplications steps: (To find Single Variable)
- Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
- Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
- Set the two products equal to each other.
- Solve for the variable.
Into how many equal parts can the same cake be cut if the cuts can only be made along the gridlines, cake can be cut into 20 equal parts.
This is further explained below.
<h3>What are
gridlines?</h3>
Generally, In spreadsheet software, gridlines are the light gray lines that divide the cells, rows, and columns. Gridlines are often used to maintain track of data. Gridlines are widely used in popular spreadsheet programs like Spreadsheet.
In conclusion, If the cuts can only be done along the gridlines, the cake may be divided into 20 equal pieces when cutting along the lines.
Read more about gridlines
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it's irrational
A rational number can be put over a fraction, while this number continues forever
a = 1, b =14 and y-coordinate is 6 when x = 0.
Solution:
Let us first write the equation of a line.
Take the points are (2, 2) and (6, 10).
Slope of the line:
m = 2
Point-slope formula:
y - 10 = 2(x - 2)
y - 10 = 2x - 4
Add 10 on both sides,we get
y = 2x + 6
Equation of a line is y = 2x + 6.
To find (a, 8), substitute x = a and y = 8 in the equation,
8 = 2a + 6
Subtract 6 from both sides, we get
2 = 2a
a = 1
To find (4, b), substitute x = 4 and y = b in the equation,
b = 2(4) + 6
b = 8 + 6
b = 14
Substitute x = o in the equation.
y = 2(0) + 6
y = 6
The y-coordinate is 6 when x = 0.
Answer:
The width of the walkway is 4 feet.
Step-by-step explanation:
The garden and a walkway around its perimeter have an area of 460 square feet.
The length of the garden = 15 feet
The width of the garden = 12 feet
Assuming that walkway is of uniform width, we can solve the following equation.
Expanding this we get;
We will solve this using quadratic equation formula:
Here a = 4 , b = 54 , c = -280
We get the roots as x = 4 and x = 
Neglecting the negative value, we will take x = 4 feet.
Hence, the width of the walkway is 4 feet.
