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3 years ago

Write an expression for the situation

Mathematics

1 answer:

MAXImum [283]3 years ago

8 0

Answer:

Step-by-step explanation:

if each brick is 3 inches tall, and there are b bricks, each b is 3, therefore 3b

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Need help with #8 & #14 PLEASE!!

juin [17]

Answer:

8 (see work)

14. 2x^2 -4x^2 +3

Step-by-step explanation:

There's attached work for explanation

8 0

3 years ago

Can you help me out

Advocard [28]

The answer is 20

Your welcome

8 0

2 years ago

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago

Match each pair of monomials with their greatest common factor. Tiles 4p4q5 and 8p3q2 24pq6 and 16p3q5 8p3q6 and 4p2q5 16p3q2 an

pashok25 [27]

The GCF of the first two is 4p³q².The GCF of the second two is 8pq⁵.The GCF of the third two is 4p²q⁵.The GCF of the fourth two is 8p²q.The GCF of the fifth two is 4p²q.
To find the GCF of each pair, find the greatest number that will divide into each coefficient. As for the variable portions, choose the variable that has the smallest exponent from each pair.

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3 years ago

Nate solve the problem 3×5 = 15 by writing and solving 15÷5 = 3 explain why Nate method works

dmitriy555 [2]

It's shust the opposite

6 0

3 years ago

Read 2 more answers