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2 years ago

6

Divide the following polynomial 27x^2-9a/3

2 answers:

ryzh [129]2 years ago

6 0

<span>(27x^2-9a)/3
= 9x^2 - 3a

hope it helps</span>

fgiga [73]2 years ago

6 0

1. (6x^3+11x^2-4x-4)/(3x-2)= (2x^2 +5x +2)
2. (y^3-4y^2+7y-6)/(y-2)= (y^2 -2y +3)
3. (x^2-4)/(x-1)= (x +1) remainder: ( -3)
4. (x^3+y^3)/(x-y)= (x^2 +xy +y^2) remainder: (2y^3)
5. (x^5+y^5)/(x+y)= (x^4 -x^3y +x^2y^2 -xy^3 +y^4)
6. (16x^2-25)/(4x+5)= (4x -5)
7. (6x^2+11x-35)/(3x-5)= (2x +7)
8. (27x^5+9x^4-18x^3)/(9x^2)= (3x^3 +x^2 -2x)
11. (2a^2+a+3)/(a-1)= (2a +3) remainder: (6)

hope this helps

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Answer:

The correct answer would be J; $\frac{1}{2} r + 2$ ;

Step-by-step explanation:

Using the algebra;

$\frac{1}{2} * r$ = $\frac{1}{2} r$

$\frac{1}{2} * 4 = 2$

Altogether this would give "J" as the answer.

Hope this helps!

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2 years ago

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attashe74 [19]

Answer:

1st even integer = 2

2nd even integer = 4

3rd even integer = 6

Step-by-step explanation:

Let the consecutive even integers be:

1st = 2(x)

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3rd = 2(x + 2) = 2x + 4

According to Given conditions:

7(2x) = 4 + 2x +2 + 2x + 4

By Simplifying:

14x = 10 + 4x

Subtracting 4x from both sides

14x - 4x = 10 + 4x -4x

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Dividing both sides by 10 we get:

x = 1

Now putting value of x in supposed integers:

1st even integer = 2(1) = 2

2nd even integer = 2(1)+2 = 4

3rd even integer = 2(1) + 4 = 6

I hope it will help you!

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3 years ago