Question

Find the x- and y- intercepts of the following equation.

Answer 1

Answer:

The x-intercept is $(4,0)$

The y-intercept is $(0,-3)$

Step-by-step explanation:

Suppose you have a function f:

$f = f(x,y) = 0$

The x-intercept is the value of x when $y = 0$.

The x-intercept is the value of y when $x = 0$.

Solution

We have:

$f(x,y) = -3x + 4y = -12$

$-3x + 4y + 12 = 0$

x-intercept

The x-intercept is the value of x when $y = 0$. So:

$-3x + 4(0) + 12 = 0$

$-3x + 12 = 0$*(-1)

$3x - 12 = 0$

$3x = 12$

$x = \frac{12}{3}$

$x = 4$

The x-intercept is $(4,0)$

y-intercept

The y-intercept is the value of y when $x = 0$. So:

$-3(0) + 4y + 12 = 0$

$4y + 12 = 0$

$4y = -12$

$y = \frac{-12}{4}$

$y = -3$

The y-intercept is $(0,-3)$