The number 42 is what percent of 35

Jacob can create an app in 24 hours, but if he works together with a friend they can create an app in 16 hours. How long would i

iogann1982 [59]

Answer:

Time taken by his friend to create the app alone = 48 hours.

Step-by-step explanation:

Hours needed by Jacob to create an app = 24 hours

$\text{One hour work of Jacob = }\frac{1}{24}$

Let hours needed by his friend in creating the app alone = x hours

$\text{So, one hour work of his friend = }\frac{1}{x}$

The both can create the app in 16 hours.

$\implies \frac{1}{24}+\frac{1}{x}=\frac{1}{16}\\\\\implies\frac{1}{x}=\frac{1}{16}-\frac{1}{24}\\\\\implies\frac{1}{x}=\frac{24-16}{24\times 16}\\\\\implies \frac{1}{x}=\frac{1}{48}\\\\\bf\implies x = 48$

Hence, Time taken by his friend to create the app alone = 48 hours.

7 0

3 years ago

The number of times a particular value a car in a data set is called what

Aloiza [94]

Its called the frequency

3 0

3 years ago

When solving negative one over five (x − 25) = 7, what is the correct sequence of operations?

miv72 [106K]

- $\frac{1}{5}$ (x-25) = 7 multiply 5 to both sides first
-(x-25) = 35 then expand the brackets
-x+25=35 make x the subject now;
-x=10
x= -10

5 0

3 years ago

If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func

nadya68 [22]

Answer:

a) C(1,000)=288,491.11 $

b) c(1,000)=288.49 $/u

c) dC/dx(1,000)=349.74 $/u

d) x=100 u

e) c=220 $/u

Step-by-step explanation:

(a) Find the total cost at a production level of 1000 units.

$C(x) = 2,000 + 160x + 4x^{3/2}\\\\C(1,000)=2,000 + 160(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=2,000+160,000+126,491.11= 288,491.11$

(b) Find the average cost at a production level of 1000 units.

$c(x)=C(x)/x\\\\c(1,000)=C(1,000)/1,000=288,491.11/1,000=288.49$

(c) Find the marginal cost at a production level of 1000 units.

$\frac{dC}{dx} =0+160+4*(3/2)x^{3/2-1}=160+6x^{1/2}\\\\dC/dx|_{1,000}=160+6*(1,000)^{1/2}=160+189.74=349.74$

(d) Find the production level that will minimize the average cost.

$c=2,000x^{-1}+160+4x^{1/2}\\\\dc/dx=2,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\-2,000x^{-2}+2x^{-1/2}=0\\\\2x^{-1/2}=2,000x^{-2}\\\\x^{-1/2+2}=1,000\\\\x^{3/2}=1,000\\\\x=1,000^{2/3}=100$

(e) What is the minimum average cost?

$c(x) = 2,000/x + 160 + 4x^{1/2}\\\\C(100)=2,000/100 + 160 + 4(100)^{1/2}=20+160+40=220$

5 0

3 years ago

Question 13 (1 point)

elixir [45]

Answer:

yo u don't get wat u saying man

7 0

3 years ago