You could actually find the compositions and thus have something to compare. You haven't shared the list of possible answer choices.
(f+g)(x) = 5x - 3 + x + 4 = 6x + 1
(f-g)(x) = 5x - 3 - x - 4 = 4x - 7
(f*g)(x) = (5x-3)((x+4) = 5x^2 + 20x - 3x - 12 = 5x^2 + 17x - 12
There are also the quotient (f/g)(x) and the compositions f(g(x)) and g(f(x)).
WRite them out.
Then you could arbitrarily select x values, such as 2, 10, etc., subst. them into each composition and determine which output is greatest.
Answer:
24% saline
Step-by-step explanation:
Find how much saline is in both solutions:
7(0.27)
= 1.89
3(0.17)
= 0.51
Add this together:
1.89 + 0.51
= 2.4
Since there are 10 quarts in total, the concentration of the mixture can be found by dividing 2.4 by 10:
2.4/10
= 0.24
So, the concentration of the mixture is 24% saline
Answer:
<em>after 4seconds</em>
Step-by-step explanation:
Given the height, h , in feet, of the football above the ground after t seconds expressed by h ( t ) = − 8 t^2 + 32 t, the height of the ball on the ground is 0feet.
Substitute h(t) = 0 into the expression and calculate t;
h ( t ) = − 8 t^2 + 32 t
0 = − 8 t^2 + 32 t
8t² = 32t
8t = 32
Divide both sides by 8
8t/8 = 32/8
<em>t = 4s</em>
<em>Hence the football hits the ground after 4seconds</em>
Answer:
0
Step-by-step explanation:
-6(n-8) = 4(12-5n)+14n
-6(n-8)=-6n+48 = 4(12-5n)+14n= 48-20n+14n
then 48-20n+14n<em> = 48-6n</em>
so you have
-6n+48 = <em>48-6n</em>
-6n+6n= n
n+48=48
n-48=48-48
n=0
Easy peasy
the bit where it says
D={something}
those are the numbers you should input for x to get y values
3.
first solve for y to make life easier
-3x-5y=20
times -1
3x+5y=-20
minus 3x both sides
5y=-3x-20
divide both sides by 5
y=-3/5x-4
sub value of the domain
x=-10
y=-3/5(-10)-4
y=6-4
y=2
a point is (-10,2)
x=-5
y=-3/5(-5)-4
y=3-4
y=-1
(-5,-1) is another
x=0
y=-3/5(0)-4
y=-4
(0,-4) is another
x=5
y=-3/5(5)-4
y=-3-4
y=-7
(5,-7)
points are (-10,2), (-5,-1), (0,-4), (5,-7)
4.
input
x=-2
y=(-2)^2-3
y=4-3
y=1
(-2,1)
x=-1
y=(-1)^2-3
y=1-3
y=-2
(-1,-2)
x=0
y=(0)^2-3
y=-3
(0,-3)
x=1
y=(1)^2-3
y=1-3
y=-3
(1,-3)
x=2
y=(2)^2-3
y=4-3
y=1
(2,1)
the points are (-2,1), (-1,-2), (0,-3), (1,-2), (-2,1)
see graph below