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3 years ago

Can someone please answer this with steps

Mathematics

1 answer:

ivanzaharov [21]3 years ago

6 0

1) Put all equations together and add them up to equal 180. Triangle's angles add up to 180°

EX) (x+10)+(3x-5)+x=180

2)Combine like terms.

EX) (5x+5)=180

3) Subtract 5 to both sides

EX) 5x=175

4) Divide both sides by 5.

EX) x=35

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The answer: 0, 4/5 and 5

Explanation: first, we factor out 2x and get: 2x(5x^2-29x+20)=0

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Juliette [100K]

Answer:

12(3+1)

Step-by-step explanation:

use distributive property to solve

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2 years ago

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the population of center city is modeled by exponential function f, where x is the number of years after the year of 2015. the g

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2 years ago

If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

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3 years ago