Let the no. of $10 bills be x, the no. of $5 bills be 2x, and the no. of $20 bills be y.
<span>A cashier collects 124 bills => x + 2x + y = 124 => 3x +y =124
</span>totaling $920 dollars => ($10)(x) + ($5)(2x) + ($20)(y) = $920 => 20x + 20y = 920
Now you got 2 equations :
3x +y =124 &
20x + 20y = 920
3x +y =124 => y=124-3x
Then Sub y=124-3x into 20x + 20y = 920,
ie. 20x + 20(124-3x) = 920
20x + 2480 - 60x = 920
2480 - 40x = 920
2480 - 920 = 40x
1560 = 40x
x = 39
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
Number Two or B would be correct
Answer:
d
Step-by-step explanation:
9(5)+8=53
All you have to do is plug 5 in for x
