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icang [17]
3 years ago
15

Brainliest for correct answer!!

Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

Step-by-step explanation:

Use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} For us that will look like this:

d=\sqrt{(6-(-3))^2+(-2-4)^2} which simplifies to

d=\sqrt{(9)^2+(-6)^2} and a bit more to

d=\sqrt{81+36} so

d=\sqrt{117}

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Hello!
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How many solutions does the following equation have?
stepan [7]

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William cycles at a speed of 15 miles per hour. he cycles for 12 miles from home to school. if he increases his cycling speed by
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3 years ago
Solve each system using a matrix
Serjik [45]

<u>ANSWER </u>


x=\frac{1}{2} and y=\frac{1}{4}



<u>EXPLANATION</u>


Given;

4x-12y=1

and

6x+4y=4

The augmented matrix of the two linear equation is given by;


\left[\begin{array}{ccc}4&-12|&-1\\6\:&\:\:\:4|&4\end{array}\right]


We now perform row operations;

\frac{1}{4}\times R_1 \rightarrow R_1.

This gives us


\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\6\:&\:\:\:4|&4\end{array}\right]



R_2-6R_1 \rightarrow R_2


\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\0\:&\:\:\:22|&\frac{11}{2}\end{array}\right]


\frac{1}{22}R _2 \rightarrow R_2


\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\0\:&\:\:\:1|&\frac{1}{4}\end{array}\right]


R_1+3R_2 \rightarrow R_1


\left[\begin{array}{ccc}1&0|&\frac{1}{2}\\0\:&\:\:\:1|&\frac{1}{4}\end{array}\right]


Hence x=\frac{1}{2} and y=\frac{1}{4}




4 0
3 years ago
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