$\frac{3 \sqrt{2} - 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \times \frac{3 \sqrt{2} - 2 \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \\ \\ = \frac{18 + 12 - 12 \sqrt{6} }{18 - 12} \\ \\ = \frac{30 - 12 \sqrt{6} }{6} \\ \\ = 5 - 2 \sqrt{6}$

7 0

3 years ago

(3x^3)( 1/9x^2 - 6 + 2x)

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

3x^3(1/9x^2-6+2x)

This question is not clear, we can not different between the numerator or denominator of some variable.

3x^3×1/9x^2-3x^3×-6+3x^3×2x

1/3x^(3+2)-18x^3+6x^(3+1)

1/3x^5-18x^3+6x^4

8 0

4 years ago

HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

saveliy_v [14]

The answer to your question is 2, I hand wrote this problem and doubled check using a website called m a t h w a y . c o m, if i knew how to insert a picture of my writing i would

6 0

4 years ago

Read 2 more answers

243^0.2x=81^x+5<br><br>Could you please help me with the steps to this problem?

Natasha_Volkova [10]

Answer:

-20/3

Step-by-step explanation:

First simplify the left side of the equation

243^(1/5x)= (243^1/5)^x

=( $\sqrt[5]{243}$ )^x