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3 years ago

(3x^3)( 1/9x^2 - 6 + 2x)

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Answer:

Step-by-step explanation:

3x^3(1/9x^2-6+2x)

This question is not clear, we can not different between the numerator or denominator of some variable.

3x^3×1/9x^2-3x^3×-6+3x^3×2x

1/3x^(3+2)-18x^3+6x^(3+1)

1/3x^5-18x^3+6x^4

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PLEASE HELP DUE TODAY

AleksAgata [21]

9514 1404 393

Answer:

16 square units

Step-by-step explanation:

When you plot the points, you see they define a trapezoid with bases of lengths 2 and 6, and a height of 4. The area formula is ...

A = (1/2)(b1 +b2)h

A = (1/2)(2 +6)(4) = 16

The area of the trapezoid is 16 square units.

4 0

2 years ago

If a triangle with vertices A(-1, 4), B(-1, -2), C(2, -2) is dilated with a scale factor of 2 and a center of dilation at the or

givi [52]

Answer:

A' (-2,8) B' (-2,-4) C' (4,-4)

Step-by-step explanation:

Dilations Rule :

(x,y) → (kx,ky)

Scale factor = K

When your scale factor is more than one our triangle gets bigger. When your scale factor is less than one our triangle gets smaller.

( you plug in 2 in every point and those are your answers).

Remember negative times negative is positive and positive times negative is negative.

5 0

2 years ago

Plz help , due in 5 mins

Grace [21]

Answer:

option a) 30 : 19

Step-by-step explanation:

$Length = 7 \frac{1}{2} = \frac{15}{2}\\\\Width = 4\frac{3}{4} = \frac{19}{4}$

Ratio of length to width:

$\frac{15}{2} : \frac{19}{4}$

$=\frac{\frac{15}{2}}{\frac{19}{4}}\\\\=\frac{15}{2 } \times \frac{4}{19}\\\\=15\times \frac{2}{19}\\\\=\frac{30}{19}\\\\30 : 19$

3 0

2 years ago

Can u help me with this

pishuonlain [190]

The answer is 10.62 meters. All you have to do is add them together to get the answer. I hope you find this answer the most helpful! :)

3 0

2 years ago

Read 2 more answers

Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

5 0

2 years ago