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3 years ago

(3x^3)( 1/9x^2 - 6 + 2x)

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Answer:

Step-by-step explanation:

3x^3(1/9x^2-6+2x)

This question is not clear, we can not different between the numerator or denominator of some variable.

3x^3×1/9x^2-3x^3×-6+3x^3×2x

1/3x^(3+2)-18x^3+6x^(3+1)

1/3x^5-18x^3+6x^4

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Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))

BartSMP [9]

By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ $\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )$
k= 0, 1 , 2, ..... , (n-1)

For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
</span>

Part (A) <span>find the modulus for all of the fourth roots
</span>
<span>∴ The modulus of the given complex number = l z l = 81
</span>
∴ The modulus of the fourth root = $\sqrt[4]{z} = \sqrt[4]{81} = 3$

Part (b) find the angle for each of the four roots

The angle of the given complex number = $\frac{3 \pi}{8}$
There is four roots and the angle between each root = $\frac{2 \pi}{4} = \frac{\pi}{2}$
The angle of the first root = $\frac{ \frac{3 \pi}{8} }{4} = \frac{3 \pi}{32}$
The angle of the second root = $\frac{3\pi}{32} + \frac{\pi}{2} = \frac{19\pi}{32}$
The angle of the third root = $\frac{19\pi}{32} + \frac{\pi}{2} = \frac{35\pi}{32}$
The angle of the fourth root = $\frac{35\pi}{32} + \frac{\pi}{2} = \frac{51\pi}{32}$

Part (C): find all of the fourth roots of this

The first root = $z_{1} = 3 ( cos \ \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})$
The second root = $z_{2} = 3 ( cos \ \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})$

The third root = $z_{3} = 3 ( cos \ \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})$
The fourth root = $z_{4} = 3 ( cos \ \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})$

7 0

4 years ago

WILL MARK BRAINLIEST!!! Find the fifth roots of 243(cos 240° + i sin 240°).

Snowcat [4.5K]

Answer:

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).

Equating equal parts and using de Moivre's theorem:

r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240

r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p

So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360

So there are 5 distinct solutions given by:

3(cos 48 + i sin 48),

3(cos 120 + i sin 120),

3(cos 192 + i sin 192),

3(cos 264 + i sin 264),

3(cos 336 + i sin 336)

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3 years ago

HELP NEEDED, GIVING BRAINLIEST!

Nataly_w [17]

The correct answer is:

B. This is a dilation about (0, 0) with a scale factor of 4; A'(8, 4), B' (16, 4), C' (16, -12).

Step-by-step explanation:

Given

Dilation: D : (x,y) => (4x,4y)

And Vertices

A ( 2, 1 ), B ( 4, 1 ), C ( 4, -3 )

Applying dilation on all vertices

$A ( 2, 1 ) => A'(4*2, 4*1) => A'(8,4)\\B ( 4, 1 ) = > B' (4*4 ,4*1) = > B'(16,4)\\C(4,-3) => C' (4*4 , 4*-3) => C'(16, -12)$

To find the scale factor,

As we are multiplying each vertex coordinate by 4, the dilation factor is 4.

Moreover,

$\frac{A'}{A} = \frac{(8,4)}{(2,1)} = (4,4)$

Hence the scale factor is 4.

So,

The correct answer is:

B. This is a dilation about (0, 0) with a scale factor of 4; A'(8, 4), B' (16, 4), C' (16, -12).

Keywords: Dilation, Scale factor

Learn more about dilation at:

#LearnwithBrainly

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3 years ago

If m(x) = x^2 + 3 and n(x) = 5x + 9, which expression is equivalent to (mn)(x)?

eduard

(x^2 + 3)(5x + 9)
5x^3 + 9x^2 + 15x + 27

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3 years ago

DNA TAC ACC TTG GCG ACG ACT Write the mRNA strand then the Amino Acid sequence.

Ugo [173]

AUG UGG AAC CGC UGC AGU

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3 years ago