4 years ago

(3x^3)( 1/9x^2 - 6 + 2x)

Mathematics

1 answer:

Veseljchak [2.6K]4 years ago

8 0

Answer:

Step-by-step explanation:

3x^3(1/9x^2-6+2x)

This question is not clear, we can not different between the numerator or denominator of some variable.

3x^3×1/9x^2-3x^3×-6+3x^3×2x

1/3x^(3+2)-18x^3+6x^(3+1)

1/3x^5-18x^3+6x^4

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