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grin007 [14]
3 years ago
9

Boxes of bad vampire novels arrive, on average, every 8 minutes at an industrial-strength shredder. The standard process to load

, shred, and unload each shredded boxload takes 6.5 minutes. What is the average time from when a box of novels arrives until shredding is complete (in hours)?
Mathematics
1 answer:
oee [108]3 years ago
8 0

Answer:

0.578 hours

Step-by-step explanation:

If boxes of books arrive at a rate of 1 per 8 minutes, the number of boxes per hour is:

\mu =\frac{1}{8}*60=7.5/hour

If the service rate is 1 box per 6.5 minutes, the number of boxes per hour is:

\mu =\frac{1}{6.5}*60=9.231/hour

The average time from when a box of novels arrives until shredding is complete is:

t=\frac{1}{\mu-\lambda}=\frac{1}{9.231-7.5} \\t=0.578\ hours

The average time in the system is 0.578 hours.

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Step-by-step explanation:

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3 years ago
Which of the following estimates at a 95% confidence level most likely comes form a small sample?
KonstantinChe [14]

OptionAStep-by-step explanation:95% confidence interval is obtained using the following formulaCOnfidence interval lower bound = mean - critical value * sigma/sq rt nand upper bound = mean + critical value*sigma/sq rt nThus margin of error = critical value*sigma/rt nvaries indirectly as n provided others are remaining the same.Hence lower sample indicates higher margin of errorOut of 4 options given we find that 1 option has maximum margin of error as 21%Hence option. A is most likely coming from a small sample.

6 0
2 years ago
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
NemiM [27]

Answer:

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2622

The margin of error is:

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In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF

The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

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Answer:

Step-by-step explanation:

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2 years ago
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