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olganol [36]
3 years ago
12

Make r the subject of the formula

2%7D%29%20%7D%20" id="TexFormula1" title="v = mg \sqrt{(1 - r {}^{2}) } " alt="v = mg \sqrt{(1 - r {}^{2}) } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
serg [7]3 years ago
4 0

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Find the measure of angle A.<br><br> 71° x+49<br> +72
slega [8]

Answer: 66 degrees

Step-by-step explanation:

Sum of the angle measures is 180, so:

71 + x + 49 + x + 72 = 180

2x + 192 = 180

2x = -12

x = -6

Meaning the measure of angle A = -6 + 72 = 66 deg.

5 0
2 years ago
Help please I don’t know how to do this
Mashcka [7]
The correct answer is the last one
(0,-4)
4 0
2 years ago
Picture below<br> ..........................
masha68 [24]

Answer:

B) Multiply each side by 3

Step-by-step explanation:

This is how to solve for h

\frac{h}{3}+ 7 = 5           (First Step --> Subtract 7 from both sides)

\frac{h}{3} =  - 2             (Second Step --> Multiply both sides by 3 to cancel out the                                 denominator and to find just h)

h = -6

6 0
3 years ago
Read 2 more answers
50 POINTS!!!!!WILL MARK BRAINLIEST IF YOU HELP<br> GEOMETRY. LOOK AT PHOTO FOR QUESTIONS
ki77a [65]

Answer:

hmm a chicken

Step-by-step explanation:

6 0
3 years ago
Someone please help with parts a b c and d. I will mark brainlest!!!
maria [59]

Answer:

A. 49 feet

B. 66 feet (round to the nearest foot)

C. 4 seg

Step-by-step explanation:

A. What is the height of the ball after 3 seconds?

For t=3 seg

h(3)=-16(3)^{2} +63(3)+4

h(3)=-144+189+4\\h(3)=-144+193\\h(3)=49 feet

B. What is the maximum height of the ball? round to the nearest foot

h(t)=-16(t)^{2} +63(t)+4\\h'(t)=-32(t) +63\\

then

-32(t)+63=0\\t=\frac{-63}{-32}\\t=1.969seg

For t=1.969seg

h(1.969)=-16(1.969)^{2}+63(1.969)+4\\h(1.969)= 66.016\\h(1.969)=66 feet

C. When will the ball hit the ground?

The ball will hit the ground when h(t)=0

so, -16t^{2} +63(t)+4=0

Using the quadratic equation

t=4seg

6 0
3 years ago
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