Answer:
Step-by-step explanation:
Like terms have same variable with same power.
r² + 5r + 3r² - 2r = r² + 3r² + 5r - 2r
= 4r² + 3r
We know the amount of water is 1 liter and the milk is 20% of that. Let y be the total amount of liquid in the bottle.
so
y=1+(0.2*1)
Answer:
f^-1(x) is 6x + 48
f(x) = 1/6x - 8
To find f^-1(x) equate f(x) to y
That's
f(x) = y
y = 1/6x - 8
Next interchange the terms
We have
x = 1/6y - 8
Make y the subject
Multiply through by 6
We have
6x = y - 48
y = 6x + 48
Therefore f^-1(x) is 6x + 48
Hope this helps you
The answer is 3. Hope this helped! Good luck! Let me know if you have any more questions! :)
Answer:
<h3>2.5secs</h3>
Step-by-step explanation:
Given the height of the ball modeled by the equation h = -16t^2+ 100, where
h is the height
t is in seconds
We can find the time taken by the ball to reach the ground.
The ball reaches the ground when the height h = 0
Substitute h = 0 into the equation and find t;
0 = -16t^2+ 100
16t^2 = 100
t^2 = 100/16
t = √100/16
t = 10/4
t = 2.5secs
Hence the ball reaches the ground after 2.5secs
