Answer:
Amanda's
Step-by-step explanation:
Given :
3/6 + 2/4
The L. C. M of 6 and 4 = 12
(6 + 6) / 12
12 / 12
= 1
Renne's result = 5/10
Amanda's result = 1 whole
Hence, Amanda's result makes more sense.
Answer: hello some part of your question is missing
Let v=〈−2,5〉 in R^2,and let y=〈0,3,−2〉 in R^3.
Find a unit vector u in R^2 such that u is perpendicular to v. How many such vectors are there?
answer:
One(1) unit vector ( < 5/√29, 2 /√29 > ) perpendicular to 〈−2,5〉
Step-by-step explanation:
let
u = < x , y > ∈/R^2 be perpendicular to v = < -2, 5 > ------ ( 1 )
hence :
-2x + 5y = 0
-2x = -5y
x = 5/2 y
back to equation 1
u = < 5/2y, y >
∴ || u || = y/2 √29
∧
u = < 5 /2 y * 2 / y√29 , y*2 / y√29 >
= < 5/√29, 2 /√29 > ( unit vector perpendicular to < -2, 5 > )
Answer: B
Step-by-step explanation:
To isolate x, you divide both sides by 21
21x=7
x = 7/21
Simplify by dividing both the numerator and denominator by 7
x = 1/3
Since, 1/3 is not an option, B is the correct answer
Answer:
• discriminant: 73
• # of real solutions: 2
Step-by-step explanation:
Comparing the equation ...
2x^2 -9x +1 = 0
to the generic form ...
ax^2 +bx +c = 0
we find the coefficient values to be ...
a = 2; b = -9; c = 1
That makes the value of the discriminant, (b^2 -4ac), be ...
(-9)^2 -4(2)(1) = 81 -8 = 73
Since the discriminant is positive, the number of real solutions is 2.
Answer:
Step-by-step explanation: