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3 years ago

15

The sum of three numbers is 50. If the third number is one-third the second number and the first number exceeds the second numbe

r by 8, then find the first number.

1 answer:

galina1969 [7]3 years ago

7 0

Answer:

second number= X

first number = X+8

third number X/3

sum of three numbers is 50.

X+X+8+X/3=50

2x+x/3=50-8

(6x+x) / 3 =42

7x =42*3

X =42*3/7

=18

Second number=18

third number= 18/3=6

first number=18+8=26

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