The sum of three numbers is 50. If the third number is one-third the second number and the first number exceeds the second numbe
r by 8, then find the first number.
1 answer:
Answer:
second number= X
first number = X+8
third number X/3
sum of three numbers is 50.
X+X+8+X/3=50
2x+x/3=50-8
(6x+x) / 3 =42
7x =42*3
X =42*3/7
=18
Second number=18
third number= 18/3=6
first number=18+8=26
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