Given: Sound Intensity ( I ) = 
We know, the approximate threshold of human hearing is at 1kHz. In watts/m^2 it's value is
⁻¹² W/m².
So, we can say, Reference sound intensity
= 10⁻¹² W/m².
We have formula for "sound intensity level LI in dB" when entering sound intensity.
LI = 10×log (I / Io) in dB
Plugging values of I and Io in formula.
LI = 10 × log (
)
LI = 10 × log (99000000)
= 10 × 7.99564
LI = 79.96 dB.
Therefore, 79.96 dB is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2.
False positives are positive results from the test of a non-infected person, which happens 100-97=3% of the time, choice C.
Answer: your answer would be A
Step-by-step explanation:
well you have the different charges and they wanna find out what the higher rate is in order to do that you have to look at the different numbers to see what is higher and the one that is higher is the one you may or may not wanna go to