<h2>1) B</h2>
<h2>2) C</h2>
<h2>3) A</h2>
<h3>do you need an explanation?</h3>
Let x = big number
Let y = small number
x + y = 66...Equation A
2y = x + 15...Equation B
We have two equations in two unknowns.
x + x + 15 = 66
2x = 66 - 15
2x = 54
x = 54/2
x = 27
Plug x = 27 into EITHER equation above to find y.
I will use Equation A.
x + y = 66
27 + y = 66
y = 66 - 27
y = 39
The two numbers are 27 and 39.
There is no way that he can run 151515km/h, but if he really can, then :
1 hour = 60 minutes
(151515km/h)/60minutes = 2525,25km/minute
