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3 years ago

Given f(x)=2x^3-3x and g(x)=-3x^2+1, what is the value of h(3) where h(x)=(f+g)(x)?

Mathematics

1 answer:

Mamont248 [21]3 years ago

3 0

Answer:

h(3) = 73

Step-by-step explanation:

The function $h(x) = f(x) + g(x) = 2x^3 -3x +3x^2 +1 = 2x^3 +3 x^2 -3x+1$

Now since you need to find the value of this new function at the point x=3, replace x by "3" in the expression above and perform the calculation:

$h(3) = 2(3)^3 +3 (3)^2 -3(3)+1=73$

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<h2>The first one:</h2>

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Step 1: Add -y to both sides.

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x+y+z+−x=2+−x

y+z=−x+2

Step 2: Add -z to both sides.

y+z+−z=−x+2+−z

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solve for z.

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x+y+z+−x=2+−x

y+z=−x+2

Step 2: Add -y to both sides.

y+z+−y=−x+2+−y

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<h2>The second one:</h2>

solve for x.

Step 1: Add y to both sides.

x−y−z+y=2+y

x−z=y+2

Step 2: Add z to both sides.

x−z+z=y+2+z

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Step 1: Add -x to both sides.

x−y−z+−x=2+−x

−y−z=−x+2

Step 2: Add z to both sides.

−y−z+z=−x+2+z

−y=−x+z+2

Step 3: Divide both sides by -1.

−y /−1 = −x+z+2 /−1

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solve for z.

Step 1: Add -x to both sides.

x−y−z+−x=2+−x

−y−z=−x+2

Step 2: Add y to both sides.

−y−z+y=−x+2+y

−z=−x+y+2

Step 3: Divide both sides by -1.

−z /−1 = −x+y+2 /−1

z=x−y−2

<h2>The third one:</h2>

solve for x.

Step 1: Add y to both sides.

x−y+z+y=−6+y

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Step 2: Add -z to both sides.

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Step 2: Add -z to both sides.

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Step 2: Add y to both sides.

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