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luda_lava [24]
3 years ago
10

Given f(x)=2x^3-3x and g(x)=-3x^2+1, what is the value of h(3) where h(x)=(f+g)(x)?

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

h(3) = 73

Step-by-step explanation:

The function h(x) = f(x) + g(x) = 2x^3 -3x +3x^2 +1 = 2x^3 +3 x^2 -3x+1

Now since you need to find the value of this new function at the point x=3, replace x by "3" in the expression above and perform the calculation:

h(3) = 2(3)^3 +3 (3)^2 -3(3)+1=73

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