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vlabodo [156]
3 years ago
12

Find the range of F

ac{2}{x-7} " alt="f(x)= \frac{2}{x-7} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
steposvetlana [31]3 years ago
6 0
Answer: y \in R; y \neq 0
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.

Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.

Now, since we know the end behaviours, let's find the asymptotic behaviours.

As x  approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.

So, our range would be: y \in R; y \neq 0
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La
Marysya12 [62]

Answer:

Step-by-step explanation:

The formula you need for this is

A(t)=P(1+\frac{r}{n})^{nt where

A(t) is the amount after a certain number of years has gone by,

P is the initial deposit,

r is the interest rate in decimal form,

n is the number of compoundings done per year, and

t is the amount of time in years.

For us,

A(t) = 11900

P is 250

r is .048

n is 12 (there are 12 months in a year)

t is our unknown. Filling in:

11900=250(1+\frac{.048}{12})^{(12)(t) which simplifies a bit to

11900=250(1_.004)^{(12t) . Now we'll divide both sides by 250:

47.6=(1.004)^{12t and then take the natural log of both sides to bring that t down out front:

ln(47.6)=ln(1.004)^{12t and then

ln(47.6) = 12t ln(1.004). Now divide both sides by ln(1.004) to isolate the 12t:

967.6383216 = 12t and divide both sides by `12 to get

t = 80.6 months which is 6.7 years

5 0
3 years ago
Simplify the expression
Crank

Answer:

First awnser

Step-by-step explanation:

4x(7-v2)+v7(7-v2)

28-4v2+7v7-v14

6 0
3 years ago
a 40 gram sample of a substance that's used for drug research has a k-value of 0.1446. find the substance's half life in days
Novay_Z [31]

The applicable decay formula is:N = No*e^(-kt)WhereN = Mass left after time tNo = Original massk = constantt = half lifeUsing the values given,N/No = e^(-0.1446t) = 1/2ln (1/2) = -0.1446 t *ln e^1-0.6931 = -0.1446 tt = 0.6331/0.1446 = 4.79 daysTherefore, half-life is 4.8 days.

3 0
3 years ago
Read 2 more answers
If Dandelion the cat runs 35 feet in 0.8 seconds, what is the speed at which she is running?(1 point)
zysi [14]

Answer:

43.75

Step-by-step explanation:

It you want to find the speed of the cat, all you have to do is divide 35 by 0.8.

3 0
3 years ago
Kevin went to see his favorite sports team play his car can go 320 miles on one lank of gas. If he used 20% of a full tank of ga
Oxana [17]

Answer:

64 miles

Step-by-step explanation:

If he used 20% of the gas, he can go 20% of the miles

20% of 320 miles

.20 * 320

64 miles

7 0
3 years ago
Read 2 more answers
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