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Savatey [412]
3 years ago
14

(7^2)^4= n^8 solve for n

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

n=7

Step-by-step explanation:

(7^2)^4= n^8

We know that a^b^c = a^(b*c)

7^(2*4) = n^8

7^8 = n^8

Since the exponents are the same, the bases must be the same

n=7

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Please help me with..... A rectangular garden is 50 feet longer than it is wide its perimeter is 284 feet
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3 years ago
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2 years ago
Read 2 more answers
-6a-7<br><img src="https://tex.z-dn.net/?f=%20-%206a%20-%207%20%5Cleqslant%2017" id="TexFormula1" title=" - 6a - 7 \leqslant 17"
seropon [69]

-6a-7\leq17\ \ \ \ |+7\\\\-6a\leq24\ \ \ \ |\text{change the signs}\\\\6a\geq-24\ \ \ |:6\\\\a\geq-4

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3 years ago
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