3 years ago

(7^2)^4= n^8 solve for n

Mathematics

1 answer:

S_A_V [24]3 years ago

4 0

Answer:

n=7

Step-by-step explanation:

(7^2)^4= n^8

We know that a^b^c = a^(b*c)

7^(2*4) = n^8

7^8 = n^8

Since the exponents are the same, the bases must be the same

n=7

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