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Savatey [412]
3 years ago
14

(7^2)^4= n^8 solve for n

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

n=7

Step-by-step explanation:

(7^2)^4= n^8

We know that a^b^c = a^(b*c)

7^(2*4) = n^8

7^8 = n^8

Since the exponents are the same, the bases must be the same

n=7

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Answer:

SEE BELOW

Step-by-step explanation:

C = 14.85

S = 16.90

c = 5.99

d = 6.99

3) 0.2(3C+2d)

round C to 15 and d to 7 cause that's about right

No cause that's about 12 and 5 is way too low.

So actually work it out now

0.2(3(14.85)+2(6.99))

0.2(44.55+13.98)

0.2(58.53)

11.706 but in terms of money it would be 11.71

4) 5S+5C+5c+5d

C is about 15, S is about 17, c is about 6, d is about 7

that is about 225

That seems reasonable.

(The real total though is 2223.65)

5) t=1.39

14.85+1.39x=20

Lets round those numbers again to make it easy to work with

15+1.5x=20

1.5x=5

x=3.33333

No, you cannot add 4 toppings and still pay $20

He over estimated

1.39x=5.15

x=3.70503597

you can get 3.

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3 years ago
Determine the similarity ratio (large to small) of the similar figures.
mrs_skeptik [129]
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2 years ago
AB, CD, and EF intersect at O. If CD is perpendicular to EF and m
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Answer:

m(∠AOF) = 148°

Step-by-step explanation:

From the figure attached,

CD intersects line EF at a point O.

Line CD is perpendicular to the line EF.

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Since m(∠COE) = m(∠AOE) + m(∠AOC) = 90°

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m(∠AOC) = 90° - 32° = 58°

m(∠AOF) = m(∠AOC) + m(∠COF)

               = 58° + 90°

               = 148°

Therefore, m(∠AOF) = 148° will be the answer.

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3 years ago
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