Answer:
Step-by-step explanation:
(-6 , 4) & (-1 , 2)
Slope = 
![= \frac{2-4}{-1-[-6]}\\\\= \frac{-2}{-1+6}\\\\= \frac{-2}{5}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B2-4%7D%7B-1-%5B-6%5D%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-2%7D%7B-1%2B6%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-2%7D%7B5%7D)
m = -2/5 & (-6 , 4)
y -y1 = m(x -x1)
![y - 4 = \frac{-2}{5}(x - [-6])\\\\y - 4 = \frac{-2}{5}(x + 6)\\\\y - 4 = \frac{-2}{5}x + 6*\frac{-2}{5}\\\\y = \frac{-2}{5}x -\frac{12}{5}+4\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{4*5}{1*5}\\\\y=\frac{-2}{5}x-\frac{12}{5}+\frac{20}{5}\\\\y=\frac{-2}{5}x+\frac{8}{5}](https://tex.z-dn.net/?f=y%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7D%28x%20-%20%5B-6%5D%29%5C%5C%5C%5Cy%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7D%28x%20%2B%206%29%5C%5C%5C%5Cy%20-%204%20%3D%20%5Cfrac%7B-2%7D%7B5%7Dx%20%2B%206%2A%5Cfrac%7B-2%7D%7B5%7D%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B-2%7D%7B5%7Dx%20-%5Cfrac%7B12%7D%7B5%7D%2B4%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx-%5Cfrac%7B12%7D%7B5%7D%2B%5Cfrac%7B4%2A5%7D%7B1%2A5%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx-%5Cfrac%7B12%7D%7B5%7D%2B%5Cfrac%7B20%7D%7B5%7D%5C%5C%5C%5Cy%3D%5Cfrac%7B-2%7D%7B5%7Dx%2B%5Cfrac%7B8%7D%7B5%7D)
Answer:
116*
Step-by-step explanation:
36* + 28* = 64*
180* - 64* = 116*
You could multiply the two numbers to get a product of 15.98 pounds.
Answer:
The lowest common denominator or least common denominator (abbreviated LCD) is the least common multiple of the denominators of a set of fractions. It is the smallest positive integer that is a multiple of each denominator in the set. Fractions write with fraction bar / like 3/4 .
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
slope intercept form :
y=m+b
m=slope
If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.
Data:
(8,4)
m=2/3
y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)
Answer: The equation of the line would be: y=2/3 x-4/3.
if we have the next slope "m",then the perendicular slope will be:
m´=-1/m
We have this equation: y=2/3 x+0; the slope is: m=2/3.
The perpendicular slope will be: m`=-1/(2/3)=-3/2
And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:
y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16
answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
