First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
Step-by-step explanation:
Frequency of Section 1 is 28 and total number of frequencies is 80.
- P(Section 1) = 28/80 = 7/20
Answer:
A. 2.8 billion years old
Step-by-step explanation:
1/16 = (1/2)^4, so 4 half-lives have elapsed.
4 · 0.700 billion years = 2.8 billion years
The rock is 2.8 billion years old.
1000 grams = 1 kilogram
2000 grams = 2 kilograms
4000 grams = 4 kilograms
7000 grams = 7 kilograms
8000 grams = 8 kilograms
4/6 will simplify to 2/3
9/12 will simplify to 3/4
Find a common denominator
12 is a good one
8/12
9/12
9/12 is greater than 4/6
